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\noindent
\begin{center}
\framebox{
\vbox{\vspace{2mm}
\hbox to 6.28in { {\bf CS~151~~~Complexity Theory
\hfill Spring 2019} }
\vspace{4mm}
\hbox to 6.28in { {\Large \hfill Problem Set #1 \hfill} }
\vspace{2mm}
\hbox to 6.28in { {\it Out: #2 \hfill Due: #3} }
\vspace{2mm}}
}
\end{center}
\vspace*{4mm}
}
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\begin{document}
\problemset{2}{April 12}{{\bf April 19}}
Reminder: you are encouraged to work in groups of two or three;
however you must turn in your own write-up and note with whom you
worked. You may consult the course notes and the text (Papadimitriou). The full honor code guidelines can be found in the course syllabus.
Please attempt all problems. {\bf To facilitate grading, please
turn in each problem on a separate sheet of paper and put your
name on each sheet. Do not staple the separate sheets.}
\begin{enumerate}
\item A {\em strong} nondeterministic Turing Machine has, in
addition to its $q_{\mbox{accept}}$ and $q_{\mbox{reject}}$
states, a special state $q_{\mbox{?}}$. Such a Turing Machine
{\em accepts} its input if all computation paths lead to
$q_{\mbox{accept}}$ and $q_{\mbox{?}}$ states, and it {\em rejects} its
input if all computation paths lead to $q_{\mbox{reject}}$ and
$q_{\mbox{?}}$ states. Moreover, on every input, there is at least
one computation path leading to $q_{\mbox{accept}}$ or
$q_{\mbox{reject}}$. Show that the class of languages decided\footnote{A language is {\em decided} (as usual) if every input is either accepted or rejected according to the accept/reject criteria for this type of machine.} by a
strong nondeterministic Turing Machine in polynomial time is
exactly $\mbox{\bf NP} \cap \mbox{\bf coNP}$.
\item In this problem you will prove Mahaney's Theorem: a sparse
language $S$ cannot be $\mbox{{\bf NP}}$-complete unless
$\mbox{\bf P} = \mbox{\bf NP}$. Throughout this problem, $S$ is a
sparse language in $\mbox{\bf NP}$ with a polynomial bound $p(n)$
on the number of strings of length at most $n$.
\begin{enumerate}
\item Explain briefly where the proof of the special case of
Mahaney's Theorem for {\em unary} languages (from class) breaks
down for sparse languages.
\item Show that if $\overline{\mbox{SAT}}$ reduces to $S$ in
polynomial time via reduction $R$, then a procedure very similar
to the one for unary languages from class decides
$\overline{\mbox{SAT}}$ in polynomial time, and hence implies
$\mbox{\bf P} = \mbox{\bf NP}$.
\item Define $c(n)$ to be the exact number of strings of length at
most $n$ in $S$ (clearly $c(n) \le p(n)$ for all $n$). Argue that
the following language is in $\mbox{\bf NP}$:
\[\hat{S} = \{ (x, 1^k) : k < c(|x|) \mbox{ or } (k = c(|x|) \mbox{ and } x \not\in S)\}.\]
Hint: do not try to compute $c(|x|)$; rather, focus on describing
an $\mbox{\bf NP}$ algorithm that decides $\hat{S}$ properly under
the assumption that $k = c(|x|)$, and then see what your algorithm
does when $k \ne c(|x|)$.
\item Finally we assume $S$ is $\mbox{\bf NP}$-complete. Thus,
everything in $\mbox{\bf NP}$ reduces to $S$, and we give names to
two of these reductions: let $T$ be a polynomial-time reduction
from $\mbox{SAT}$ to $S$, and let $U$ be a polynomial-time
reduction from $\hat{S}$ to $S$. Using $T$ and $U$, describe a
{\em family} of ``candidate reductions from
$\overline{\mbox{SAT}}$ to $S$,'' $R_k$, with the following
properties:
\begin{eqnarray*}
R_k(\phi) \in S && \mbox{ if $k < c(|T(\phi)|)$} \\
R_k(\phi) \in S \Leftrightarrow \phi \in
\overline{\mbox{SAT}} && \mbox{ if $k = c(|T(\phi)|)$} \\
R_k(\phi) \not\in S && \mbox{ if $k > c(|T(\phi)|)$}
\end{eqnarray*}
\item Using parts (b) and (d), prove Mahaney's Theorem. You may
need to modify part (b) slightly so that on a given input $\phi$,
the procedure only applies $R$ to formulae $\phi'$ for which
$|\phi'| = |\phi|$. This should require at most a syntactic
change: we can think of any partial assignment of values to
variables in $\phi$ as having the same length as $\phi$ if we
don't perform any simplification.
\item Argue that if $\mbox{\bf P} = \mbox{\bf NP}$, then there
{\em are} sparse $\mbox{\bf NP}$-complete languages (under
polynomial-time, many-one reducibility).
\end{enumerate}
\item A directed graph $G = (V, E)$ is {\em strongly connected} if
for every pair of vertices $(x, y)$ there is a directed path from
$x$ to $y$ and a directed path from $y$ to $x$. Consider STRONGLY
CONNECTED, the language of graphs $G$ that are strongly connected.
Either show that this problem is in $\mbox{\bf L}$, or prove a
complexity consequence of such a containment.
\end{enumerate}
\end{document}